Let the radius of the smaller cone be r cm
Diameter of bigger cone = 40 cm
the radius = 20 cm and height = 9 cm
\[\begin{array}{*{35}{l}}
Volume\text{ }of\text{ }larger\text{ }cone\text{ }=\text{ }1/3\text{ }\pi \text{ x }{{\left( 20 \right)}^{2}}~x\text{ }9 \\
The\text{ }volume\text{ }of\text{ }the\text{ }smaller\text{ }cone\text{ }=\text{ }1/3\text{ }\pi \text{ x }{{r}^{2}}~x\text{ }108 \\
\end{array}\]
Volume of larger cone = 3 x Volume of smaller cone
\[\begin{array}{*{35}{l}}
1/3\text{ }\pi \text{ x }{{\left( 20 \right)}^{2}}~x\text{ }9\text{ }=\text{ }3\text{ x }\left( 1/3\text{ }\pi \text{ x }{{r}^{2}}~x\text{ }108 \right) \\
{{r}^{2}}~=\text{ }{{\left( 20 \right)}^{2}}~x\text{ }9/\text{ }\left( 108\text{ x }3 \right) \\
r\text{ }=\text{ }20/6\text{ }=\text{ }10/3\text{ }cm \\
\end{array}\]