$\int{_{\frac{-\pi }{4}}^{\frac{\pi }{4}}\frac{dx}{1+\sin x}=\int{_{-\frac{\pi }{4}}^{\frac{\pi }{4}}\frac{{{\sec }^{2}}\left( \frac{x}{2} \right)}{{{\tan }^{2}}\left( \frac{x}{2} \right)+1}dx}}$

contexto.140

3 years ago