(i) (- 1, – 2), (1, 0), (- 1, 2), (- 3, 0)
(ii) (- 3, 5), (3, 1), (0, 3), (- 1, – 4)
Solution:
(i) Let the points (- 1, – 2), (1, 0), ( – 1, 2), and ( – 3, 0) represent the quadrilateral’s vertices A, B, C, and D, respectively.
AB
BC
CD
DA
AC
BD
Length of side= AB = BC = CD = DA = 
Measure of diagonal = AC = BD = 4
As a result, the specified points are the vertices of square.
(ii) The vertices A, B, C, and D of the given quadrilateral are represented by the points (- 3, 5), (3, 1), (0, 3), and ( – 1, – 4).
AB
BC
CD
AD
Points A, B, and C are also seen to be collinear.
As a result, the given points can only form a triangle with three sides, rather than a quadrilateral with four sides.
As a result, the given points cannot form a quadrilateral in general.