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contexto.140

3 years ago

$\begin{array}{l} 4 \sqrt{3} x^{2}+5 x-2 \sqrt{3}=0 \\ \Rightarrow 4 \sqrt{3} x^{2}+8 x-3 x-2 \sqrt{3}=0 \\ \Rightarrow 4 x(\sqrt{3} x+2)-\sqrt{3}(\sqrt{3} x+2)=0 \\ \Rightarrow(\sqrt{3} x+2)(4 x-\sqrt{3})=0 \\ \Rightarrow \sqrt{3} x+2=0 \text { or } 4 x-\sqrt{3}=0 \\ \Rightarrow x=-\frac{2}{\sqrt{3}}=-\frac{2 \sqrt{3}}{3} \text { or } x=\frac{\sqrt{3}}{4} \end{array}$

Hence, and are the roots of the given equation.