x + 3 > 0 and 2x < 14
Let us consider the first inequality.
![\[\begin{array}{*{35}{l}} x\text{ }+\text{ }3\text{ }>\text{ }0 \\ x\text{ }+\text{ }3\text{ }-\text{ }3\text{ }>\text{ }0\text{ }-\text{ }3 \\ x\text{ }>\text{ }-3 \\ \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-dfc75ce889515d41fcf97d064809bcaf_l3.png "Rendered by QuickLaTeX.com")
Now, let us consider the second inequality.
2x < 14
Divide both the sides by 2 we get,
2x/2 < 14/2
x < 7
∴ The solution of the given system of inequation is (–3, 7).
x + 3 > 0 and 2x < 14
Let us consider the first inequality.
Now, let us consider the second inequality.
2x < 14
Divide both the sides by 2 we get,
2x/2 < 14/2
x < 7
∴ The solution of the given system of inequation is (–3, 7).