Choose the correct answer The point on the curve x^ 2 = 2y which is nearest to the point (0, 5) is (A) (2 2,4) (B) (2 2,0) (C) (0, 0) (D) (2, 2)

Equation of the curve is                                                                                 ……….(i)

Let P be any point on the curve (i), then according to question,

Distance between given point (0, 5) and P =   (say)

 

=             [From eq. (i)]

 

  = Z (say)

  and 

Now 

 

 

At 

 [Positive]

 Z is minimum and  is minimum at 

 From eq. (i)

 

  and  are two points on curve (i) which are nearest to (0, 5).

Therefore, The correct option is option (A) .