Find the roots of the given equation:

contexto.140

3 years ago

$\begin{array}{l} 3 \sqrt{7} x^{2}+4 x-\sqrt{7}=0 \\ \Rightarrow 3 \sqrt{7} x^{2}+7 x-3 x-\sqrt{7}=0 \\ \Rightarrow \sqrt{7} x(3 x+\sqrt{7})-1(3 x+\sqrt{7})=0 \\ \Rightarrow(3 x+\sqrt{7})(\sqrt{7}-1)=0 \\ \Rightarrow 3 x+\sqrt{7}=0 \text { or } \sqrt{7} x-1=0 \\ \Rightarrow x=\frac{-\sqrt{7}}{3} \text { or } x=\frac{1}{\sqrt{7}}=\frac{1 \times \sqrt{7}}{\sqrt{7} \times \sqrt{7}}=\frac{\sqrt{7}}{7} \end{array}$

Hence, the roots of the equation are and .