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A man spends 6.4 kJ energy in displacing a body by 64 m in the direction in which he applies force, in 2.5 s. Calculate: (i) the force applied and (ii) the power spent (in H.P) by the man.
A man spends 6.4 kJ energy in displacing a body by 64 m in the direction in which he applies force, in 2.5 s. Calculate: (i) the force applied and (ii) the power spent (in H.P) by the man.
Class 10 | ICSE | Physics | Selina | Work Energy
A man spends 6.4 kJ energy in displacing a body by 64 m in the direction in which he applies force, in 2.5 s. Calculate: (i) the force applied and (ii) the power spent (in H.P) by the man.

Solutions:

According to the question –

Work done by man is 6.4 kJ

64 m is the distance moved

(i) Then, the work done by the man is

Work = Force × distance moved in direction of force

Upon substituting values, we get –

6.4 × 103 = F × 64

Or, F = (6.4 × 103) / 64

F = 100 N

(ii) Power spent is as follows

= (6.4 × 103) / 2.5 = 2560 W

We know that 1 H.P = 746 W

So, 1 W = 1 / 746 H.P

We get, 2560 W = 2560 / 746 H.P

Power = 3.43 H.P

i

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