Noon Academy
Let
and
Compute
contexto.140
3 years ago
Solution:
Concluded:
![\begin{array}{l} \left.5 A-3 B+4 C=5\left(\left[\begin{array}{ccc} 0 & 1 & -2 \\ 5 & -1 & -4 \end{array}\right]\right)-3\left(\begin{array}{ccc} 1 & -3 & -1 \\ 0 & -2 & 5 \end{array}\right]\right)+4\left(\left[\begin{array}{ccc} 2 & -5 & 1 \\ -4 & 0 & 6 \end{array}\right]\right) \\ \left.\left.=\left(\left[\begin{array}{ccc} 0 & 5 & -10 \\ 25 & -5 & -20 \end{array}\right]\right)-\left(\begin{array}{ccc} 3 & -9 & -3 \\ 0 & -6 & 15 \end{array}\right]\right)+\left(\begin{array}{ccc} 8 & -20 & 4 \\ -16 & 0 & 24 \end{array}\right]\right) \\ =\left[\begin{array}{ccc} -3 & 14 & -7 \\ 25 & 1 & -35 \end{array}\right]+\left[\begin{array}{ccc} 8 & -20 & 4 \\ -16 & 0 & 24 \end{array}\right] \\ =\left[\begin{array}{ccc} 5 & -6 & -3 \\ 9 & 1 & -11 \end{array}\right] \end{array}](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-205ebf18edcc2eebd228d4d1dce70dae_l3.png "Rendered by QuickLaTeX.com")
![5 A-3 B+4 C=\left[\begin{array}{ccc}5 & -6 & -3 \\ 9 & 1 & -11\end{array}\right]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-4900c18df0b15e4519f9e224cb5cd695_l3.png "Rendered by QuickLaTeX.com")
![A=\left[\begin{array}{ccc}0 & 1 & -2 \\ 5 & -1 & -4\end{array}\right], B=\left[\begin{array}{ccc}1 & -3 & -1 \\ 0 & -2 & 5\end{array}\right]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-41e2731669cc626117fcfaab4c782d70_l3.png "Rendered by QuickLaTeX.com")
![C=\left[\begin{array}{ccc}2 & -5 & 1 \\ -4 & 0 & 6\end{array}\right] .](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-ec6db1baabfa8122c2209e13ff3fac41_l3.png "Rendered by QuickLaTeX.com")
