Solution:
Option(C) ids correct.
To Find: The value of 
Now, let 
Here, range of principle value of 
![[0, \pi]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-3ee8a7f2b7324e2152a4807a1b912cfc_l3.png "Rendered by QuickLaTeX.com")
![\Rightarrow x=\frac{13 \pi}{6} \notin[0, \pi]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-d36e3696e4b74bf7a5ec4bf8969ca43b_l3.png "Rendered by QuickLaTeX.com")
Hence for all values of 
Mark the tick against the correct answer in the following: The value of 
Solution:
Option(C) ids correct.
To Find: The value of
Now, let
Here, range of principle value of
Hence for all values of
