Solution:
Option(A) is correct.
To Find: The value of 
Now, let 
Here range of principle value of sec is ![[0, \pi]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-3ee8a7f2b7324e2152a4807a1b912cfc_l3.png "Rendered by QuickLaTeX.com")
![\Rightarrow \mathrm{x}=\frac{\ln }{5} \notin[0, \pi]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-403a822f62de8d1fbe2a4403001ade2a_l3.png "Rendered by QuickLaTeX.com")
Hence for all values of 
Mark the tick against the correct answer in the following: The value of 
A. 
B. 
C. 
D. none of these
