The inductance of the inductor can be considered as 
The capacitance of the capacitor will be , 
The resistance of the resistor as per question is 
As we know, resonant frequency can be calculated by the relation given below,
Now, Q – value of the circuit can be calculated by the relation stated below:
![\[Q=\frac{1}{R} \sqrt{\frac{L}{C}}=\frac{1}{10} \sqrt{\frac{2}{32 \times 10^{-6}}}=\frac{1}{10 \times 4 \times 10^{-3}}=25\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-4e35f777a71002af19330432349c1bc7_l3.png "Rendered by QuickLaTeX.com")
Thus , the Q – value of the question given above will be 25