At the point when Cu2+ particle is treated with KI, a white hasten is shaped. Clarify the response with the assistance of the compound condition. contexto.130 3 years ago Solution: Cu2+ gets decreased to Cu+, and I–gets oxidized to I2.
![\[~2Cu2+\text{ }+\text{ }4I-\to \text{ }Cu2I2\text{ }+\text{ }I2\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-af6b01355f0aa2d1fb1118fd0d5faed1_l3.png "Rendered by QuickLaTeX.com")
