By using properties of determinants, show that: Vinay 3 years ago (i) LHS = [operating and ] = = = R.H.S. (ii) L.H.S. = = = = [operating and ] = = = = R.H.S. Proved.
![\[\text { (i) }\left|\begin{array}{ccc} x+4 & 2 x & 2 x \\ 2 x & x+4 & 2 x \\ 2 x & 2 x & x+4 \end{array}\right|=(5 x+4)(4-x)^{2}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-761ecebc01ac7ac73d668008d102850f_l3.png "Rendered by QuickLaTeX.com")
![\[\text { (ii) }\left|\begin{array}{ccc} y+k & y & y \\ y & y+k & y \\ y & y & y+k \end{array}\right|=k^{2}(3 y+k)\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-96eaf73e0a5c4da52bd9f5777af34135_l3.png "Rendered by QuickLaTeX.com")