Classify the following function as injection, surjection or bijection: f: R → R, defined by

) Given f: R → R, defined by 

   

Now we have to check for the given function is injection, surjection and bijection condition.

Injection condition:

Let x and y be any two elements in the domain (R), such that f(x) = f(y).

f(x) = f(y)

   

   

   

   

   

   

So, f is not an injection.

Surjection test:

Let y be any element in the co-domain (R), such that f(x) = y for some element x in R (domain).

f(x) = y

   

   

   

   

, which may not be in R

For example, if 

   

, then

   

, which is not in R

So, f is not surjection and f is not bijection.