Development of gas in a vacuum is called free extension. Ascertain the work is done and the adjustment of inner energy when 1 liter of an ideal gas grows isothermally into a vacuum until its complete volume is 5 liter? Vinay 3 years ago solution: Work done in vacuum is determined by : For isothermal extension Consequently ∆U will be 0.
![\[\begin{array}{*{35}{l}} -\text{ }w\text{ }=\text{ }Text\text{ }\left( Vinitial\text{ }\text{ }Vfinal\text{ } \right) \\ ~ \\ Pext=\text{ }0 \\ ~ \\ \text{ }w\text{ }=\text{ }0x\left( 5-1 \right)\text{ }=\text{ }0. \\ ~ \\ \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-429bcf3921876e110281ce1aa52397c9_l3.png "Rendered by QuickLaTeX.com")
![\[\begin{array}{*{35}{l}} q=o \\ ~ \\ q=\text{ }U\text{ }+\text{ }\left( -\text{ }w \right) \\ \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-c09aed003555263bffd9b9070e8e4696_l3.png "Rendered by QuickLaTeX.com")
