![\[\begin{array}{*{35}{l}} 2A\text{ }+\text{ }B\text{ }\to \text{ }C\text{ }H\text{ }=\text{ }400\text{ }kJ\text{ }mol1 \\ ~ \\ what's\text{ }more,\text{ }S\text{ }=\text{ }0.2\text{ }kJ\text{ }K1\text{ }mol1 \\ \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-dda209e4073843cae616fbc6002155e5_l3.png "Rendered by QuickLaTeX.com")
Solution:
From the articulation,
![\[G\text{ }=\text{ }H\text{ }\text{ }TS\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-f4e148a9e04c893b97f2e1c9c7b830b9_l3.png "Rendered by QuickLaTeX.com")
Expecting the response at balance,
∆T for the response would be:
![\[\begin{array}{*{35}{l}} \left( G\text{ }=\text{ }0\text{ }at\text{ }balance \right) \\ ~ \\ T\text{ }=\text{ }2000\text{ }K \\ \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-8cc51acee294c553c2f327bb7fc04206_l3.png "Rendered by QuickLaTeX.com")
For the response to be unconstrained, ∆G should be negative. Consequently, for the offered response to be unconstrained, T ought to be more prominent than 2000 K.