Calculation:
P4O6 + 6H2O → 4H3PO3
4H3PO3 + 8NaOH → Na2HPO3 + 8H20
P4O6 + 8NaOH → 4Na2HPO3 + 2H2O
Moles of P4O6 = 1.1/220 = 0.5
Acid formed by one mole of P4o6 requires = 8 mol
Acid formed by 0.005 mol of NaOH is present in 100mL solution
0.04 of NaOH is present in solution = 1000/0.1 *0.04 = 400mL