Solution: Given, 
![\[=0.00241 mol L ^{-1}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-769cb84da1d68e60837d8831cbe0adb0_l3.png "Rendered by QuickLaTeX.com")
As we know, molar conductivity,
Substituting the value of known parameters we have,
![\[\begin{aligned}&=\frac{7.896 \times 10^{-5} S cm ^{-1}}{0.00241 mol L^{-1}} \times \frac{1000 cm ^{3}}{L} \&=32.76 S cm ^{2} mol ^{-1}\end{aligned}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-93dfc7f898ef77865b24196253fa1ef7_l3.png "Rendered by QuickLaTeX.com")
Also, given in question,
![\[\Lambda_{m}^{0}=390.5 S cm ^{2} mol ^{-1}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-a7d0c50c9e325aa8ea7c5bd6e20a1d43_l3.png "Rendered by QuickLaTeX.com")
We know that,
![\[\begin{aligned}&\alpha=\frac{\Lambda_{m}}{\Lambda_{m}^{0}} \&=\frac{32.76 S cm ^{2} mol ^{-1}}{390.5 Scm ^{2} mol ^{-1}}\end{aligned}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-d05561d4122763545cb882bb73a2c461_l3.png "Rendered by QuickLaTeX.com")
![\[=0.084\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-7f967972feafac4d0e4882593a9400c8_l3.png "Rendered by QuickLaTeX.com")
We know that, Dissociation constant,
![\[\begin{aligned}&=\frac{\left(0.00241 mol L^{-1}\right)(0.084)^{2}}{(1-0.084)} \&=1.86 \times 10^{-5} mol L ^{-1}\end{aligned}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-f3cc521097764f9d2fe4a832f13c8cc0_l3.png "Rendered by QuickLaTeX.com")
Conductivity of 
As we know, molar conductivity,
Also, given in question,
We know that,
We know that, Dissociation constant,
