![\[CaO\left( s \right)\text{ }+\text{ }CO2\left( g \right)\text{ }\to \text{ }CaCO3\left( s \right)\text{ };\text{ }\Delta fH\Theta \text{ }=\text{ }\text{ }178.3\text{ }kJ\text{ }mol1\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-09765da93303511a8d85bc4ef9576452_l3.png "Rendered by QuickLaTeX.com")
solution:
The given response
![\[CaO\left( s \right)\text{ }+\text{ }CO2\left( g \right)\text{ }\to CaCO3\left( s \right)\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-6e03a4a5d337ae730ed39d5684de21e7_l3.png "Rendered by QuickLaTeX.com")
is demonstrating that it is happening in the standard type of 1 mole of every substance. What’s more, the molar enthalpy of development
![\[\Delta fH\Theta \text{ }=\text{ }\text{ }178.3\text{ }kJ\text{ }mol1\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-03fa53f15e2e87a4555a14c588cf1645_l3.png "Rendered by QuickLaTeX.com")
Given for CaCO3 is additionally showing the standard conditions.
![\[So,\Delta fH\Theta \text{ }=\text{ }\text{ }178.3\text{ }kJ\text{ }mol1\text{ }=\text{ }\Delta r\text{ }H\theta \]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-4d16b3d7a956a868c2c9847bfc443afb_l3.png "Rendered by QuickLaTeX.com")
.