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Home » Standard molar enthalpy of arrangement, Δf Hθis simply a unique instance of enthalpy of response, Δr Hθ. Is the Δr Hθfor the accompanying response same as Δf Hθ? Offer the justification behind your response.    
Standard molar enthalpy of arrangement, Δf Hθis simply a unique instance of enthalpy of response, Δr Hθ. Is the Δr Hθfor the accompanying response same as Δf Hθ? Offer the justification behind your response.

    \[CaO\left( s \right)\text{ }+\text{ }CO2\left( g \right)\text{ }\to \text{ }CaCO3\left( s \right)\text{ };\text{ }\Delta fH\Theta \text{ }=\text{ }\text{ }178.3\text{ }kJ\text{ }mol1\]

CBSE | Chemistry | Class 11 | Exercise 1 | NCERT Exemplar | Thermodynamics
Standard molar enthalpy of arrangement, Δf Hθis simply a unique instance of enthalpy of response, Δr Hθ. Is the Δr Hθfor the accompanying response same as Δf Hθ? Offer the justification behind your response.

    \[CaO\left( s \right)\text{ }+\text{ }CO2\left( g \right)\text{ }\to \text{ }CaCO3\left( s \right)\text{ };\text{ }\Delta fH\Theta \text{ }=\text{ }\text{ }178.3\text{ }kJ\text{ }mol1\]

solution:

 

The given response

    \[CaO\left( s \right)\text{ }+\text{ }CO2\left( g \right)\text{ }\to CaCO3\left( s \right)\]

is demonstrating that it is happening in the standard type of 1 mole of every substance. What’s more, the molar enthalpy of development

    \[\Delta fH\Theta \text{ }=\text{ }\text{ }178.3\text{ }kJ\text{ }mol1\]

Given for CaCO3 is additionally showing the standard conditions.

 

    \[So,\Delta fH\Theta \text{ }=\text{ }\text{ }178.3\text{ }kJ\text{ }mol1\text{ }=\text{ }\Delta r\text{ }H\theta \]

.

 

i

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