Given
22.3 joules of work (W) are performed on the system while the gas transitions between states A and B.
This is an example of an adiabatic process.
As a result, the change in heat is zero.
So, ΔQ = 0
ΔW = – 22.3 (Since the work is done on the system)
From the first law of thermodynamics, we have:
ΔQ = ΔU + ΔW
Where, ΔU = Change in the internal energy of the gas
Hence,
ΔU = ΔQ – ΔW
= 0 – (-22.3 J)
We get,
ΔU = + 22.3 J
When a gas transitions from state A to state B as a result of a process, the net heat absorbed by the system is as follows.
ΔQ = 9.35 cal = 9.35 x 4.19 J
On calculation, we get,
= 39.1765 J
Heat absorbed, ΔQ = ΔU + ΔW
Thus, ΔW = ΔQ – ΔU
ΔW= 39.1765 – 22.3 = 16.8765 J
Hence, 16.88 J of work is done by the system