Solution:
As per the question,
= Total number of families
= Number of families buying newspaper
= Number of families buying newspaper
= Number of families buying newspaper
= Number of families buying newspaper A and B
= Number of families buying newspaper B and C
= Number of families buying newspaper A and C
= Number of families buying all three newspapers
Let U be the total number of families
Let A be the number of families buying newspaper A
Let B be the number of families buying newspaper B
Let C be the number of families buying newspaper C
(a) No. of families that buy A newspaper only
Percentage of families that buy A newspaper only
No. of families which buy A newspaper only
As a result, there are 3300 families which buy A newspaper only
(b) The number of families which buy none of the newspaper A, B and C.
Percentage of families which either buy A, B and C.
Percentage of families which buy none of A, B and C.
Total percentage – No. of students who play either
No. of families which buy none of A, B and C.
As a result, there are 4000 families which buy none of A, B and C.