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Home » A block of mass 15 kg is placed on a long trolley. The coefficient of static friction between the block and the trolley is 0.18. The trolley accelerates from rest with 0.5 ms-2 for 20 s and then moves with uniform velocity. Discuss the motion of the block as viewed by (a) a stationary observer on the ground, (b) an observer moving with the trolley.
A block of mass 15 kg is placed on a long trolley. The coefficient of static friction between the block and the trolley is 0.18. The trolley accelerates from rest with 0.5 ms-2 for 20 s and then moves with uniform velocity. Discuss the motion of the block as viewed by (a) a stationary observer on the ground, (b) an observer moving with the trolley.
CBSE | Laws of Motion | Physics | Physics
A block of mass 15 kg is placed on a long trolley. The coefficient of static friction between the block and the trolley is 0.18. The trolley accelerates from rest with 0.5 ms-2 for 20 s and then moves with uniform velocity. Discuss the motion of the block as viewed by (a) a stationary observer on the ground, (b) an observer moving with the trolley.

The block’s mass is 15 kg.

Static friction coefficient between the block and the trolley, p= 0.18

The trolley accelerates at a rate of 0.5 m/s2.

(a) The force experienced by the block, F = ma = 15 x 0.5 = 7.5 N, acts in the trolley’s direction of travel.

Ff=p mg = 0.18 x 15 x 10 = 27 N Friction force

The block will be subjected to less force than the friction. As a result, the block will remain stationary. As a result, the block will remain motionless for a stationary observer on the ground.

(b) The spectator is travelling at a faster rate than the trolley. He creates an inertial frame in which Newton’s rules of motion no longer apply. For the observer travelling with the trolley, the trolley will be at rest.

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