Consider AB as the height of the kite A and AC as the string
Angle of elevation of the kite = 260 32’
Take AB = x m and AC = 100 m
We know that
sin θ = AB/AC
Substituting the values
sin 260 32’ = x/100
So we get
0.4467 = x/100
By further calculation
x = 100 × 0.4467
x = 44.67 = 44.7 m
Hence, the height of the kite is 44.7 m.
Hence Proved