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Home » A cyclist starts from centre O of a circular park of radius 1 km and moves along the path OPRQO as shown in the figure. If he maintains constant speed of 10 m/s, what is his acceleration at point R in magnitude and direction?
A cyclist starts from centre O of a circular park of radius 1 km and moves along the path OPRQO as shown in the figure. If he maintains constant speed of 10 m/s, what is his acceleration at point R in magnitude and direction?
CBSE | Class 11 | Motion in a Plane | NCERT | Physics
A cyclist starts from centre O of a circular park of radius 1 km and moves along the path OPRQO as shown in the figure. If he maintains constant speed of 10 m/s, what is his acceleration at point R in magnitude and direction?

Answer:

The circular path has a radius of 1 km, with O as the center and R as the distance between the two points.
The biker is moving at a speed of 10 meters per second.
As a result, it is possible to say that the motion is a uniform circular motion at the point R.
As a result, R = 1000 metres.
v = 10 metres per second
Therefore, acceleration, ac = v2/R = 0.1 m/s2 along RO.
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