Solution:
Consider
AB as the lamp post
CD is the height of man
BD is the distance of man from the foot of the lamp
FD is the shadow of man
Construct CE parallel to DB
Take AB = x and CD = 1.8 m
EB = CD = 1.8 m
AE = x – 1.8
Shadow FD = 5.4 m
In right triangle ACE
tan θ = AE/CE
Substituting the values
tan θ = (x – 1.8)/ 3.6 …… (1)
In right triangle CFD
tan θ = CD/FD
Substituting the values
tan θ = 1.8/5.4 = 1/3 ….. (2)
Using both the equations
(x – 1.8)/ 3.6 = 1/3
So we get
3x – 5.4 = 3.6
3x = 3.6 + 5.4 = 9.0
By division
x = 9/3 = 3.0
Hence, the height of lamp post is 3 m.