A solid cylinder of mass 20 \mathrm{~kg} rotates about its axis with angular speed 100 \mathrm{rad} \mathrm{s}^{-1}. The radius of the cylinder is 0.25 \mathrm{~m}. What is the kinetic energy associated with the rotation of the cylinder? What is the magnitude of angular momentum of the cylinder about its axis?
A solid cylinder of mass 20 \mathrm{~kg} rotates about its axis with angular speed 100 \mathrm{rad} \mathrm{s}^{-1}. The radius of the cylinder is 0.25 \mathrm{~m}. What is the kinetic energy associated with the rotation of the cylinder? What is the magnitude of angular momentum of the cylinder about its axis?

Mass of the cylinder is given as m=20 \mathrm{~kg}

Angular speed is given as \omega=100 \mathrm{rad} \mathrm{s}^{-1}

Radius of the cylinder is given as r=0.25 \mathrm{~m}

So, the moment of inertia of the solid cylinder can be calculated as,
\mathrm{I}=\mathrm{mr}^{2} / 2
=(1 / 2) \times 20 \times(0.25)^{2}
=0.625 \mathrm{~kg} \mathrm{~m}^{2}

(a) \therefore Kinetic energy will be =(1 / 2) \mid \omega^{2} =(1 / 2) \times 0.625 \times(100)^{2}=3125 J

(b) Angular momentum will be L=\mid \omega