A speeding motorcyclist sees traffic jam ahead of him. He slows down to 36 \mathrm{~km} / hour. He finds that traffic has eased and a car moving ahead of him at 18 \mathrm{~km} / hour is honking at a frequency of 1392 \mathrm{~Hz}. If the speeds of sound is 343 \mathrm{~m} / \mathrm{s}, the frequency of the honk as heard by him will be
Option A \quad 1332 \mathrm{~Hz}
Option B \quad 1372 \mathrm{~Hz}
Option C \quad 1412 \mathrm{~Hz}
Option D \quad 1454 \mathrm{~Hz}
A speeding motorcyclist sees traffic jam ahead of him. He slows down to 36 \mathrm{~km} / hour. He finds that traffic has eased and a car moving ahead of him at 18 \mathrm{~km} / hour is honking at a frequency of 1392 \mathrm{~Hz}. If the speeds of sound is 343 \mathrm{~m} / \mathrm{s}, the frequency of the honk as heard by him will be
Option A \quad 1332 \mathrm{~Hz}
Option B \quad 1372 \mathrm{~Hz}
Option C \quad 1412 \mathrm{~Hz}
Option D \quad 1454 \mathrm{~Hz}

The correct option is C

Apparent frequency can be calculated as,

f^{\prime}=f_{0}\left(\frac{v \pm v_{0}}{v \pm v_{s}}\right)

\mathrm{f}^{\prime}=\mathrm{f}_{0}\left(\frac{\mathrm{v}+\mathrm{v}_{0}}{\mathrm{v}+\mathrm{v}_{\mathrm{s}}}\right)

=1392\left(\frac{343+10}{343+5}\right)

=1412 \mathrm{HZ}