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Home » A spring having with a spring constant is mounted on a horizontal table as shown in Fig. 14.24. A mass of is attached to the free end of the spring. The mass is then pulled sideways to a distance of and released.
A spring having with a spring constant 1200 \mathrm{~N} \mathrm{~m}^{-1} is mounted on a horizontal table as shown in Fig. 14.24. A mass of 3 \mathrm{~kg} is attached to the free end of the spring. The mass is then pulled sideways to a distance of \mathbf{2}, \mathbf{0} \mathbf{~ c m} and released.
CBSE | Class 11 | NCERT | Oscillations | Physics
A spring having with a spring constant 1200 \mathrm{~N} \mathrm{~m}^{-1} is mounted on a horizontal table as shown in Fig. 14.24. A mass of 3 \mathrm{~kg} is attached to the free end of the spring. The mass is then pulled sideways to a distance of \mathbf{2}, \mathbf{0} \mathbf{~ c m} and released.

Determine the maximum speed of the mass.

Solution:

Spring constant is given as \mathrm{k}=1200 \mathrm{~N} \mathrm{~m}^{-1}

Mass is given as \mathrm{m}=3 \mathrm{~kg}
Displacement is given as \mathrm{A}=2.0 \mathrm{~cm}

=0.02 \mathrm{~m}

Maximum velocity is given as v_{\max }=A \omega

On substituting the values we get,

\begin{array}{l} =\mathrm{A} \sqrt{\mathrm{k}} / \mathrm{m} \\ =0.02 \mathrm{x}(\sqrt{1200 / 3)} \\ =0.4 \mathrm{~m} / \mathrm{s} \end{array}

As a result, the maximum velocity of the mass is 0.4 \mathrm{~m} / \mathrm{s}

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