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Home » A stone of mass 0.25 kg tied to the end of a string is whirled round in a circle of radius 1.5 m with a speed of 40 rev./min in a horizontal plane. What is the tension in the string? What is the maximum speed with which the stone can be whirled around if the string can withstand a maximum tension of 200 N?
A stone of mass 0.25 kg tied to the end of a string is whirled round in a circle of radius 1.5 m with a speed of 40 rev./min in a horizontal plane. What is the tension in the string? What is the maximum speed with which the stone can be whirled around if the string can withstand a maximum tension of 200 N?
CBSE | Class 11 | Laws of Motion | NCERT | Physics
A stone of mass 0.25 kg tied to the end of a string is whirled round in a circle of radius 1.5 m with a speed of 40 rev./min in a horizontal plane. What is the tension in the string? What is the maximum speed with which the stone can be whirled around if the string can withstand a maximum tension of 200 N?

The stone weighs 0.25 kilogramme.

r = 1.5 m Radius

n= 40/60 = (23) rev/sec is the number of revolutions per second.

= 2n = 2 x 3.14 x (23) is the angular velocity.

The centripetal force is provided by the tension on the string.

T = mω2r

T = 0.25 x 1.5 x [2 x 3.14 x (⅔)]

2

= 6.57 N

Maximum tension on the string, Tmax= 200 N

Tmax= mv2max/r

v2max = (Tmax x r)/m

= ( 200 x 1.5)/0.25 = 1200

vmax = 34. 6 m/s

Therefore, the maximum speed of the stone is 34.64 m/s

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