Answer:
Argument Used: x2 = π2 is irrational
So, x = π is irrational.
p: “If x2 is irrational, then x is rational.”
Consider,
An irrational number given by x = √k [k is a rational number]
Squaring both sides,
x2 = k
x2 is a rational number and contradicts our statement.
The argument is wrong.