To find: Differentiation of (x2 + 2x – 3) (x2 + 7x + 5)
Formula used: (i) (uv)′ = u′v + uv′ (Leibnitz or product rule)
(ii)

Putting the above obtained values in the formula :-
(uv)′ = u′v + uv′
[(x2 + 2x – 3) (x2 + 7x + 5)]’
= (2x + 2) × (x2 + 7x + 5) + (x2 + 2x – 3) × (2x + 7)
= 2×3 + 14×2 + 10x + 2×2 + 14x + 10 + 2×3 + 7×2 + 4×2 + 14x – 6x – 21
= 4×3 + 27×2 + 32x – 11
Ans) 4×3 + 27×2 + 32x – 11