Answer : (i) f: R → R such that f(x) = x2
Since the value of x is squared, f(x) will always be equal or greater than 0.
∴ the range is [0, ∞)
- g: R → R such that g(x) = x2 + 1
Since, the value of x is squared and also adding with 1, g(x) will always be equal or greater than 1.
∴ Range of g(x) = [1, ∞)
- h: R → R such that h(x) = sin x
We know that, sin (x) always lies between -1 to 1
∴ Range of h(x) = (-1, 1)