Answer:

This expression contains 26 terms.

11^th term from the end is the (26 − 11 + 1) ^th term from the beginning.

T₁₆ = T₁₅₊₁ = ²⁵C₁₅ (2x)^25-15 (-1/x²)¹⁵

T₁₆ = ²⁵C₁₅ (2¹⁰) (x)¹⁰ (-1/x³⁰)

T₁₆ = – ²⁵C₁₅ (2¹⁰ / x²⁰)

11^th term from the beginning.

T₁₁ = T₁₀₊₁ = ²⁵C₁₀ (2x)^25-10 (-1/x²)¹⁰

T₁₁ = ²⁵C₁₀ (2¹⁵) (x)¹⁵ (1/x²⁰)

T₁₁ = ²⁵C₁₀ (2¹⁵ / x⁵)