Answer:
we know that the mean position of the oscillator at x with PE is
= 1/2 kx2
Therefore, PE = -m2x2
When PE is maximum, KE = 0 at x = A
We get, E = 1/2 mω2A2
PE = 1/2 total energy
x2 = 1/2 A2
x = ± A/√2
Find the displacement of a simple harmonic oscillator at which its PE is half of the maximum energy of the oscillator.
Find the displacement of a simple harmonic oscillator at which its PE is half of the maximum energy of the oscillator.