Find the eccentricity, coordinates of the foci, equations of directrices and length of the latus-rectum of the hyperbola. 2x^2 – 3y^2 = 5
Find the eccentricity, coordinates of the foci, equations of directrices and length of the latus-rectum of the hyperbola. 2x^2 – 3y^2 = 5

    \[2{{x}^{2}}-\text{ }3{{y}^{2}}~=\text{ }5\]

Given:

The equation

    \[=>\text{ }2{{x}^{2}}-\text{ }3{{y}^{2}}~=\text{ }5\]

The equation can be expressed as:

RD Sharma Solutions for Class 11 Maths Chapter 27 – Hyperbola - image 27

The obtained equation is of the form

RD Sharma Solutions for Class 11 Maths Chapter 27 – Hyperbola - image 28

Where,

    \[a\text{ }=\text{ }\surd 5/\surd 2\text{ }and\text{ }b\text{ }=\text{ }\surd 5/\surd 3\]

Eccentricity is given by:

RD Sharma Solutions for Class 11 Maths Chapter 27 – Hyperbola - image 29

Foci: The coordinates of the foci are

    \[\left( \pm ae,\text{ }0 \right)\]

RD Sharma Solutions for Class 11 Maths Chapter 27 – Hyperbola - image 30

    \[\left( \pm ae,\text{ }0 \right)\text{ }=\text{ }\left( \pm 5/\surd 6,\text{ }0 \right)\]

The equation of directrices is given as:

RD Sharma Solutions for Class 11 Maths Chapter 27 – Hyperbola - image 31

The length of latus-rectum is given as:

    \[2{{b}^{2}}/a\]

RD Sharma Solutions for Class 11 Maths Chapter 27 – Hyperbola - image 32