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Home » Find the equation of the hyperbola, referred to its principal axes as axes of coordinates, in the following cases: conjugate axis is 7 and passes through the point (3, -2)
Find the equation of the hyperbola, referred to its principal axes as axes of coordinates, in the following cases: conjugate axis is 7 and passes through the point (3, -2)
CBSE | Class 11 | Exercise 27.1 | Hyperbola | Maths | RD Sharma
Find the equation of the hyperbola, referred to its principal axes as axes of coordinates, in the following cases: conjugate axis is 7 and passes through the point (3, -2)

conjugate axis is

    \[7\]

and passes through the point

    \[\left( 3,\text{ }-2 \right)\]

Given:

Conjugate axis

    \[=\text{ }7\]

Passes through the point

    \[\left( 3,\text{ }-2 \right)\]

Conjugate axis is

    \[2b\]

So,

    \[2b\text{ }=\text{ }7\]

    \[b\text{ }=\text{ }7/2\]

So,

    \[{{b}^{2}}~=\text{ }49/4\]

The Equation of hyperbola is given as

RD Sharma Solutions for Class 11 Maths Chapter 27 – Hyperbola - image 56

Since it passes through points

    \[\left( 3,\text{ }-2 \right)\]

RD Sharma Solutions for Class 11 Maths Chapter 27 – Hyperbola - image 57

    \[{{a}^{2}}~=\text{ }441/65\]

The equation of hyperbola is given as:

RD Sharma Solutions for Class 11 Maths Chapter 27 – Hyperbola - image 58

∴ The Equation of hyperbola is

    \[65{{x}^{2}}-\text{ }36{{y}^{2}}~=\text{ }441\]

i

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