Find the equation of the parabola, which is symmetric about the y-axis and passes through the point P(2, -3).
Find the equation of the parabola, which is symmetric about the y-axis and passes through the point P(2, -3).

Answer:

 

 

 

 

 

 

The equation of a parabola with vertex at the origin and symmetric about the y-axis is x2 = 4ay

The  point P(2,-3) passes through above parabola,

22 = 4a(-3)

4 = -12a

a = -1/3

The equation of a parabola is,

x2 = 4. (-1/3)y

x2 = -4/3 y

3x2 = -4y