Find the equation of the parabola with focus F(0, -3) and directrix y = 3.
Find the equation of the parabola with focus F(0, -3) and directrix y = 3.

Answer:

 

 

 

 

 

Given,

The equation of directrix is,

y = 3

y – 3 = 0

Above equation is of the form, y – a = 0

Focus of the parabola F(0,-3) is of the form F(0,-a)

a = 3

For directrix with equation y-a=0 and focus (0,-a),

The equation of the parabola is,

x2 = – 4ay

x2 = – 12y