Answer:
Given,
4sin x cos x + 2sin x + 2cos x + 1 = 0
⇒ 2sin x (2cos x + 1) + 2cos x + 1 = 0
(2cos x + 1) (2sin x + 1) = 0
Answer:
Given,
4sin x cos x + 2sin x + 2cos x + 1 = 0
⇒ 2sin x (2cos x + 1) + 2cos x + 1 = 0
(2cos x + 1) (2sin x + 1) = 0