From a point P on level ground, the angle of elevation of the top of a tower is 300. If the tower is 100 m high, how far is P from the foot of the tower?
From a point P on level ground, the angle of elevation of the top of a tower is 300. If the tower is 100 m high, how far is P from the foot of the tower?

Solution:

Consider AB as the tower and P is at a distance of x m from B which is the foot of the tower.

Height of the tower = 100 m

Hence, the distance of P from the foot of the tower is 173.2 m.

Hence Proved