Solution:
Consider AB as the building where AB = 20 m
CD as the monument where CD = x m
Take the distance between the building and the monument as y
In right triangle BCD
tan θ = CD/BD
Substituting the values
tan 450 = x/y
1 = x/y
x = y …… (1)
In right triangle ABD
tan 150 = AB/BD = 20/x
Substituting the values
0.2679 = 20/x
So we get
x = 20/0.2679 = 74.65 m
Hence, the height of the monument is 74.65 m.