Solution:-

From the question, cos θ = .7258

In the table of cosines, look for a value (≤ .7258) which is sufficiently close to .7258.

We find the value .7254 occurs in the horizontal line beginning with 43^o and in the column headed by 30’ and in the mean difference, we see .7258 – .7254 = .0004 in the column of 2’.

So we get, θ = 43^o 30’ – 2’ = 43^o 28’.

(i) θ = 43° 30′ – 2’

= 43° 28′.

(ii) 2 tan θ – sin θ

Substitute the value θ,

= 2 tan43°28′ – sin43°28′

= 2 (.9479) – .6879

= 1.8958 – .6879

= 1.2079

Therefore, the value of 2 tan θ – sin θ is 1.2079