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Home » If ( – 1, 3) and (????, β) are the extremities of the diameter of the circle x2 + y2 – 6x + 5y – 7 = 0, find the coordinates (????, β).
If ( – 1, 3) and (????, β) are the extremities of the diameter of the circle x2 + y2 – 6x + 5y – 7 = 0, find the coordinates (????, β).
CBSE | Circles | Class 11 | Exercise 21B | Maths | RS Aggarwal
If ( – 1, 3) and (????, β) are the extremities of the diameter of the circle x2 + y2 – 6x + 5y – 7 = 0, find the coordinates (????, β).

Answer:

Given,

x2 + y2 – 6x + 5y – 7 = 0

Centre (3, -5/2)

( – 1, 3) & (????, β) are the 2 extremities of the diameter

Using mid – point formula,

\begin{array}{l} \frac{{\alpha - 1}}{2} = 3\\ \alpha = 7\\ \frac{{\beta + 3}}{2} = - \frac{5}{2}\\ \beta = - 8\\ (\alpha ,\beta ) = (7, - 8) \end{array}

 

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