Answer:
Coefficient of the r term in the expansion of (1 + x)n – nCr-1
Coefficients of the (2r + 1) and (r + 2) terms in the given expansion are 43C2r+1-1 and 43Cr+2-1
Equaling two coefficients,
43C2r+1-1 = 43Cr+2-1
43C2r = 43Cr+1
2r = r + 1 or 2r + r + 1 = 43 [ nCr = nCs => r = s (or) r + s = n]
2r – r = 1 or 3r + 1 = 43
r = 1 or 3r = 43 – 1
r = 1 or 3r = 42
r = 1 or r = 42/3
r = 1 or r = 14
∴ r = 14