Substituting z = x + iy, we get,
We know,
Comparing real and imaginary parts,
And 0 = y + 2
⇒ y = -2
Substituting the value of y in
⇒ 2x = 1
Hence, x = ½
Hence, z = x + iy
= ½ – 2i
Substituting z = x + iy, we get,
We know,
Comparing real and imaginary parts,
And 0 = y + 2
⇒ y = -2
Substituting the value of y in
⇒ 2x = 1
Hence, x = ½
Hence, z = x + iy
= ½ – 2i