Solution:

Consider CB = x and DB = y

AB = 300 m

In right triangle ACD

tan θ = AB/CB

Substituting the values

tan 45⁰ = 300/x

1 = 300/x

So we get

x = 300 m

In right triangle ADB

tan θ = AB/DB

Substituting the values

tan 60⁰ = 300/y

√3 = 300/y

By further calculation

y = 300/√3

Multiply and divide by √3

y = 300/√3 × √3/√3 = 300√3/3

So we get

y = 100 × 1.732 = 173.2 m

Here

CD = x – y = 300 – 173.2 = 126.8 = 127 m

Hence, the distance between two objects is 127 m.