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Home » In vertical circular motion, the ratio of kinetic energy of a particle at highest point to that at lowest point isA) 5 B) 2 C) 0.5D) 0.2
In vertical circular motion, the ratio of kinetic energy of a particle at highest point to that at lowest point is
A) 5
B) 2
C) 0.5
D) 0.2
Physics
In vertical circular motion, the ratio of kinetic energy of a particle at highest point to that at lowest point is
A) 5
B) 2
C) 0.5
D) 0.2

Answer is (D)
\mathrm{K} . \mathrm{E}=\frac{1}{2} \mathrm{mv}^{2}
At lowest point in vertical circular motion. V_{L}=\sqrt{5 r g} and at highest point V_{h}=\sqrt{r g}
\therefore \quad \frac{(\mathrm{K} . \mathrm{E})_{\mathrm{h}}}{(\mathrm{K} . \mathrm{E})_{\mathrm{L}}}=\frac{1}{5}=0.2

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