Answer : (i) Given:
f(x) = x + 1 and g(x) = 2x -3
- To find: (f + g) (x) (f + g) (x) = f(x) + g(x)
= (x + 1) + (2x -3)
= x + 1 + 2x – 3
= 3x – 2
Therefore,
(f + g) (x) = 3x -2
- To find: (f – g) (x) (f – g) (x) = f(x) – g(x)
= (x + 1) – (2x -3)
= x + 1 – 2x + 3
= 4 – x
Therefore,
(f – g) (x) = 4 – x
- To find: (fg)(x) (fg)(x) = f(x). g(x)
= (x+1) (2x-3)
= x(2x) -3(x) +1(2x) -1(3)
= 2×2 – 3x + 2x -3
= 2×2 – x -3
Therefore,
(fg)(x) = 2×2 – x -3
(iv) To find
Sol
- Therefore,